Question

Write the coefficient of x2 in (6x -)​

Answer 1

Answer:

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Step-by-step explanation:

here's your answer

(i) Coefficient ofx2 in the following

6πx+x2−1, Coefficient of x2=1

(ii) 3x−5, coefficient of x2=0

(iii) (x−1)(3x−4)=3x−7x+4

Now coefficient of x2=3

(iv) (2x−5)(2x2−3x+1)

=4x2−6x2+2x−10x215x−5

=4x2−6x2+17x−5

Coefficient of x2=−16

Answer 2

(i) Coefficient ofx

2

in the following

6

π

x+x

2

−1, Coefficient of x

2

=1

(ii) 3x−5, coefficient of x

2

=0

(iii) (x−1)(3x−4)=3x−7x+4

Now coefficient of x

2

=3

(iv) (2x−5)(2x

2

−3x+1)

=4x

2

−6x

2

+2x−10x

2

15x−5

=4x

2

−6x

2

+17x−5

Coefficient of x

2

=−16