Question

Write the coefficient of x2

in each of the following :

(i)

π 2 –1

6

x + x (ii) 3x – 5

(iii) (x –1) (3x –4) (iv) (2x –5) (2x2

– 3x + 1)​

Answer 1

Answer:

(i) (π/6) x + x2−1 (π/6) x + x2−1 = (π/6) x + (1) x2−1 The coefficient of x2 in the polynomial (π/6) x + x2−1 = 1. (ii) 3x – 5 3x – 5 = 0x2 + 3x – 5 The coefficient of x2 in the polynomial 3x – 5 = 0, zero. (iii) (x – 1) (3x – 4) (x – 1)(3x – 4) = 3x2 – 4x – 3x + 4 = 3x2 – 7x + 4 The coefficient of x2 in the polynomial 3x2 – 7x + 4 = 3. (iv) (2x – 5) (2x2 – 3x + 1) (2x – 5) (2x2 – 3x + 1

Answer 2

Answer:

Coefficient ofx

2

in the following

6

π

x+x

2

−1, Coefficient of x

2

=1

(ii) 3x−5, coefficient of x

2

=0

(iii) (x−1)(3x−4)=3x−7x+4

Now coefficient of x

2

=3

(iv) (2x−5)(2x

2

−3x+1)

=4x

2

−6x

2

+2x−10x

2

15x−5

=4x

2

−6x

2

+17x−5

Coefficient of x

2

=−16