Question

Write the coefficient of x² in the following polynomial p(x) = (x-2) (3+1).​

Answer 1

Answer:

Coefficient of x

2

in ax

2

+bx+c=0 is a.

Hence, coefficients of x

2

in

(i) 2+x

2

+x is 1

(ii) 2−x

2

+x

3

is −1

(iii)

2

π

x

2

+x is

2

π

(iv)

2

x−1 is 0

Answer 2

Answer:

Step-by-step explanation:

$p(x)=(x-2)(3+1)\\(x-2)(3+1)=3x+(x*1)+(-2*3)+(-2*1)\\ = 3x+x-6-2\\ = 4x-8$

according to general form of quadratic polynomial

$ax^{2} +bx+c=0$

ie, $0x^{2} +4x-8$

hence coefficient of $x^{2}$ is $0$

i'm not sure if this is correct or not!