Math, asked by ooOPoisonousQueenOoo, 28 days ago

Write the coefficients of x2 in each of the following
(i) 2 + x2 + x
(ii) 2 – x2 + x3
(iii) π2 x2 + x
(iv) √2 x – 1​

Answers

Answered by Anonymous
3

\bf \huge\purple{ANSWER}

\bf\red{coficient  \: of  \: x²  \: in  \: given  \: polynomial  }

  • \bf\red{i.e\: 2 + x²+ x \:  is \:  1}

\bf\green{coficient  \: of  \: x²  \: in  \: given  \: polynomial \:}

  • \bf\green{i.e\: 2 – x² + x³  \: is \: - 1}

\bf\blue{coficient  \: of  \: x²  \: in  \: given  \: polynomial}

  • \bf\blue{i.e \: π²/2 x²+ x   \: is \: π/2}

\bf {coficient  \: of  \: x²  \: in  \: given  \: polynomial}

  • \bf {i.e \: \ \sqrt{2x} - 1   \: is \: 0}

\bf \huge\purple{THANKS}

Answered by LaRouge
1

Answer:

Question: Write the coefficients of x² in each of the following:

[Total: 4 Average: 4.3]

(i) 2 + x2 + x

(ii) 2 – x2 + x3

(iii) (π/2)x2 + x

(iv) √2x – 1

Solution 2:

(i) 2 + x2 + x , the coefficient of x2 is 1

(ii) 2 – x2 + x3, the coefficient of x2 here is -1.

(iii) (π/2)x2 + x, here the coefficient of x2 is π/2.

(iv) √2x – 1, the coefficient of x2 is 0.

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