Question

write the complex number 4+3i/(2+3i)(4-3i) in the form A+iB​

Answer 1

Answer:

A+Bi =86/325 - 75 /325i

Step-by-step explanation:

4+3i/17+6i conjugate you will get answer

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. refer attachment

Answer 2

Step-by-step explanation:

• 4+3i/(2+3i)(4-3i)
• 4+3i/8-6i+12i-9i^2 (i^2=-1)
• 4+3i/8+6i-(-9)
• 4+3i/8+6i+9
• 4+3i/17+6i (conjugate)
• (4+3i/17+6i)(17-6i/17-6i)
• 68-24i-51i-18i^2/(17^2)-(6i^2)
• 68-75i-(-18)/289-(-6)
• 68+18-75i/289+6
• 86-75i/325
• A+iB=86/325-i(75/325)