write the conditions and irrigation facilities in penamakuru villag
Answers
Answer:
Given the dimensions of cylindrical water tank, spherical solid balls and the amount of water present in the tank check if water tank will overflow when balls are dipped in the water tank.
Examples :
input : H = 10, r = 5
h = 5
N = 2, R = 2
output : Not in overflow state
Explanation :
water tank capacity = 3.14 * r * r * H
= 3.14 * 5 * 5 * 10
= 785
volume of water in tank = 3.14 * r * r * h
= 3.14 * 5 * 5 * 5
= 392.5
Volume of balls = N * (4/3) * 3.14 * R * R * R
= 2 * (4/3) * 3.14 * 2 * 2 * 2
= 67.02
Total volume of water + dip balls = 392.5 + 67.02
= 459.52
Total volume (459.02) < tank capacity (785)
So, there is no overflow in tank
input : H = 5, r = 3
h = 3
N = 3, R = 2
output : Overflow
Explanation:
water tank capacity = 3.14 * r * r * H
= 3.14 * 3 * 3 * 5
= 141.3
volume of water in tank = 3.14 * r * r * h
= 3.14 * 3 * 3 * 3
= 84.78
volume of balls = N * (4/3) * 3.14 * R * R * R
= 3 * (4/3) * 3.14 * 2 * 2 * 2
= 100.48
Total volume of water + dip balls = 84.78 + 100.48
= 185.26
Total volume (185.26) > tank capacity (141.3)
So, tank will overflow
Approach:
When solid balls are dipped in water, level of water increases, hence volume of water will also increase.
Increasing in water volume = Total volume of dip balls
Volume of Cylinder = 3.14 * r * r * h
where: r: radius of tank
h: height of tank
Number of balls are n
Balls have shape of Sphere
Volume of Sphere = (4/3) * 3.14 * R * R * R
Where R: Sphere's(solid ball) radius
After dipping all balls, if the total volume of water and all balls is less than or equal to the total volume of tank capacity then there will no overflow in tank, otherwise there will be overflow.
Below is the implementation of above approach: