Question

write the conjugate of the following surds: (√7 - √3)​

Answer 1

Answer:

We know that the when sum of two terms and the difference of the Same two terms are multiplied,the Product is always a rational Number.

Let us applying this Concept to a binomial Surd (7-√3).

When we Multiply this with the difference of the Same two terms, that is, With (7-√3), the Product is :

(7 + \sqrt{3} )(7 - \sqrt{3} ) = (7 {)}^{2} - ( \sqrt{3} {)}^{2} = 49 - 3 = 46.(7+

3

)(7−

3

)=(7)

2

−(

3

)

2

=49−3=46.

( \: {a}^{2} - {b}^{2} = (a + b)(a - b)(a

2

−b

2

=(a+b)(a−b)

Since, 46 is a rational Number.

Hence, (7+√3) is a Conjugate of (7-√3)

Step-by-step explanation:

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