Question

*Write the conjugate pair of √7+3√5
* 1️⃣ 3√5 + √7 2️⃣ √5 + 3√7 3️⃣ - √7 + 3√5 4️⃣ - √7 - 3√5​

Answer 1

Answer:

3−5

The complex conjugate of a complex number is the number with an equal real part and an imaginary part equal in magnitude but opposite in sign.

The conjugate of 3+5 is 3−5.

Answer 2

To Find :- The conjugate pair of √7+3√5 :-

1) 3√5 + √7

2) √5 + 3√7

3) - √7 + 3√5

4) - √7 - 3√5

Concept used :-

• A conjugate pair is a pair of numbers whose product is a real integers .
• A conjugate is formed by changing the sign between two terms in a binomial .
• conjugate pair of a + b is a - b .
• conjugate pair of √a + √b = √a - √b .
• conjugate pair of a + b√c = a - b√c .

Solution :-

The conjugate pair of √7+3√5 :-

→ √7 + 3√5

→ 3√5 + √7

changing the sign between terms now,

→ 3√5 - √7

→ -√7 + 3√5 (Ans.)

Verification :-

→ (√7 + 3√5)(-√7 + 3√5)

→ (3√5 + √7)(3√5 - √7)

using (a + b)(a - b) = a² - b²

→ (3√5)² - (√7)²

→ 9*5 - 7

→ 45 - 7

→ 38 = Real integer .

therefore, the conjugate pair of √7+3√5 is equal to (3) (-√7 + 3√5) .

Learn more :-

solution of x minus Y is equal to 1 and 2 X + Y is equal to 8 by cross multiplication method

https://brainly.in/question/18828734