*write the consequences of bursting cracker (1)air quality(in particular of delhi)
Answers
Explanation:
Given:
(6^{5} )^{4}(6
5
)
4
To find:
The value of (6^{5} )^{4}(6
5
)
4
Solution:
(6^{5} )^{4}(6
5
)
4
Use the rule of the exponents to simplify expression,
⇒ (6^{5} )^{4}(6
5
)
4
{ {(x^a)^b=x^{ab}}(x
a
)
b
=x
ab
}
To raise a power to another power, multiply the exponents,
⇒6^{5X4}6
5X4
Multiply 5 times 4,
⇒6^{20}6
20
It can be written as,
⇒2^{20}2
20
×3^{20}3
20
⇒3.6561583.656158 ×10^{15}10
15
So the final answer is 3.6561583.656158 ×10^{15}10
15
Answer:
Delhi has had the distinction of being one of the most polluted cities in the world, especially in the winter months from October—January. These months coincide with the religious festival of Diwali. It is argued that air quality gets worse in the aftermath of Diwali on account of firecrackers that get burned during the festival. We use hourly data on PM 2.5 particulate concentration from 2013 to 2017 to estimate the Diwali effect on air quality in Delhi. We improve on existing work by using the event study technique as well as a difference-in-difference regression framework to estimate the Diwali effect on air quality. The results suggest that Diwali leads to a small, but statistically significant increase in air pollution. The effect is different across locations within Delhi. To our knowledge, this is the first causal estimate of the contribution of Diwali firecracker burning to air pollution.