write the converse of: oppositeangles of a cyclic quadrilateral are supplementary.
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- We can use that theorem to prove its own converse: that if two opposite angles of a quadrilateral are supplementary, then the quadrilateral is cyclic. ... Since it is not cyclic, the circle that goes through A, B, and C must not also go through D'.
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We can use that theorem to prove its own converse: that if two opposite angles of a quadrilateral are supplementary, then the quadrilateral is cyclic. The proof is by contradiction. ... By assumption, D' is supplementary to B. But by the theorem we proved above, D is also supplementary to B and therefore congruent to D'.
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