Question

Write the correct set of four quantum number for the valence electron (outermost electron) of potassium (z = 19 ) .

Answer 1

The four quantum number for an atom refers to the state of valence electrons

the four numbers are

n is the distance of electron from nucleus and be 1,2,3,4 etc.

l is the shape of orbital of electrone from 0 to n-1

m¹ is the orientation the orbital ranging from -l to +l and

m² is the spin property of the electrone either +1/2 or ,-1/2

For k atom the electronic configuration is 1s²2s²2p63s²3p64s1 which means that n is 4

It also means the since the outermost electrone in s orbital l=0

m¹ can range from -l to. +l, but id l,is 0 because in s orbital then m¹ must be 0 to

m² can be either +1/2 or -1/2 depending on the spin of the electrone it doesn't particular matter in that case

there for the full set of quantam no fir k atoms is 4,0,0+- 1/2

Hope its help

Answer 2

Answer:

Explanation:For Atom with At.no. 19

i.e for K electronic configuration is 1s² 2s² 2p6 3s² 3p6 4s¹

Outermost electron is 4s¹

Here n=4

l=0 for s-subshell

For l=0 'm' has 0 value ranging from -l to +l

And for single electron spin quantum no. is +½