Write the count the number of even numbers in a vector using r
Answers
Answer:
am working through the Euler Problems, and the problem is to sum the even terms in a Fibonacci sequence up to the length where the last term is < 4e6. I got it eventually but the following method of counting the even numbers did not work, and I am curious as to why.
First, this method of counting even numbers from a sequence works:
numbers <- 1:32 N <- length(numbers) total <- rep(0,N) for (i in numbers){ if(i %% 2 == 0) total[i] <-i } sum(total) #272
If the remainder when num is divided by 2 equals to 0, it's an even number. If not, it's an odd integer.
Program to check if the input number is odd or even.
# A number is even if division by 2 give a remainder of 0.
# If remainder is 1, it is odd.
num = as.integer(readline(prompt="Enter a number: "))
if((num %% 2) = 0) {print(paste(num,"is Even"))} else {print(paste(num,"is Odd"))}
Output 1
Enter a number: 89
[1] "89 is Odd"
Output 2
Enter a number: 0
[1] "0 is Even"
In this program, we ask the user for the input (an integer) which is stored in num variable.
If the remainder when num is divided by 2 equals to 0, it's an even number. If not, it's an odd integer.
To learn more about R programming
https://brainly.in/question/13131191
T o learn more about even number
https://brainly.in/question/34846119
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