Question

write the cube of (4x+1)3​

Answer 1

$by \: using \: formule \: \: \: (a + b) ^{3} = {a}^{3} + {b}^{3} + 3ab(a + b) \\ \\ so \: (4x + 1) ^{3} = ({4x})^{3} + {1}^{3} + 3(4x)(1)(4x + 1) \\ = 64 {x}^{3} + 1 + (12x)(4x + 1) \\ = 64 {x}^{3} + 1 + 48 {x}^{2} + 12x \\ = 64 {x}^{3} + 48 {x}^{2} + 12x + 1$