write the cube of four natural numbers which are multiples of 3 and verify that the cube of a natural number which is multiple and 3 is a multiple of 27
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Answer:
sandhyapravinsharma
12.10.2019
Math
Secondary School
answered
Write cubes of five natural numbers which are multiples of 3 and verify the following:
The cube of a natural number which is a multiple of 3 is a multiple of 27
2
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manjulapatil04
Answer:
multiples of 3 are 3, 6, 9, 12, 15.
cube of 3 is 27 which is a multiple of three.
cube of 6 is 216 which is a multiple of 27.
cube of 9 is 729 which is a multiple of 27.
cube of 12 is 1728 which is a multiple of 27
.
cube of 15 is 3375 which is a multiple of 27.
Thus, the cube of a natural number which is a multiple of 3 is a multiple of 27
Answer:
As we know that the first 5 natural numbers which are multiple of 3 are 3, 6, 9, 12 and 15 So now, The cube of 3, 6, 9, 12 and 15 33 = 3 × 3 × 3 = 27 63 = 6 × 6 × 6 = 216 93 = 9 × 9 × As we know that the first 5 natural numbers which are multiple of 3 are 3, 6, 9, 12 and 15 So now, The cube of 3, 6, 9, 12 and 15 33 = 3 × 3 × 3 = 27 63 = 6 × 6 × 6 = 216 93 = 9 × 9 × 9 = 729 123 = 12 × 12 × 12 = 1728 153 = 15 × 15 × 15 = 3375 All the cubes are divisible by 27 ∴ “The cube of a natural number which is a multiple of 3 is a multiple of 27