write the cubes of (3a+4b)3
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By using identity
(a+b) ^3 =(a-b) (a^2 +b^2 +ab)
We get
(3a-4b)(9a^2 +16b^2 +24ab)
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4
ĀNSWĒR ⬆⬆⬆⬆⬆⬆⬆

✌✔✔✔✔✔✳^_^✴
✌✔✔✔✔✔✳^_^✴
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