write the cubes of 5 natural numbers which are multiple of 3 and verify the following: the cubes of a natural numbers which is a multiply of 3 is of 27
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9square =81
3square=9
6square=36
12square=144
15square=225
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Five natural numbers, which are multiples of 3, are 3, 6, 9, 12 and 15. It is evident that the cubes of the above multiples of 3 could be written as multiples of 27. Thus, it is verified that the cube of a natural number, which is a multiple of 3, is a multiple of 27.
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