Question

write the cubes of three natural numbers which are multiples of 5 verify that all such cubes are multiples of 125​

Answer 1

Answer:

(3)

3

=3×3×3=27

(6)

3

=6×6×6=216

(9)

3

=9×9×9=729

(12)

3

=12×12×12=1728

(15)

3

=15×15×15=3375

Verification:

(3)

3

=27=27×1

(6)

3

=216=27×8

(9)

3

=729=27×27

(12)

3

=1729=27×64

(15)

3

=3375=27×125

∴ 'The cube of natural number, which is a multiple of 3 is a multiple of 27'.