write the cubic polynomial whose zeros are first three natural numbers
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The given zeros are −3,−1 and 2
So, the factors of the polynomial are (x−(−3)),(x−(−1)) and (x−2)
Then the polynomial
P(x)=(x−(−3))(x−(−1))(x−2)
=(x+3)(x+1)(x−2)
=(x
2
+4x+3)(x−2)
=x
3
−2x
2
+4x
2
−8x+3x−6
=x
3
+2x
2
−5x−6
Hence, the polynomial is x
3
+2x
2
−5x−6
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