Write the decomposition reaction of calcium carbonate and how many moles of CO2are there in this equation
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Answer:
Explanation:
Chemical reaction involved is:
CaCO 3
→CaO+CO 2
Molar mass of CaCO 3
=40+12+16×3=100 g
According to the balanced reaction 100 g of CaCO 3
produces 1 mol of CO 2
i.e. 22.4 L at STP.
∴50 g CaCO 3
will produce 100
22.4 ×50=11.2 L CO 2 at STP.
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