Question

Write the derivative of sin x w.r.t. cos x

Answer 1

Answer:

$\frac{d(sinx)}{d(cosx)}=-cotx$

Step-by-step explanation:

I have applied chain rule to find derivaative of the given function.

Let y= sinx

Then

$\frac{dy}{dx}=cosx$

Take u=cosx

$\frac{du}{dx}=-sinx$

By chain rule

$\frac{dy}{du}=\frac{dy}{dx}\:\frac{dx}{du}$

$\frac{dy}{du}=\frac{\frac{dy}{dx}}{\frac{du}{dx}}$

Now,

$\frac{d(sinx)}{d(cosx)}$

$=\frac{dy}{du}$

$=\frac{\frac{dy}{dx}}{\frac{du}{dx}}$

$=\frac{cosx}{-sinx}$

$=-cotx$

Answer 2

Answer:See the attachment

Step-by-step explanation:thk u...