write the dimension of a and b in the relation E= a+x²/bt
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1
Answer:
a= {L^2} and b = {M^-1 T}
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★ Brainly Teacher ★
E = ( b -x²) /at
= ( b/at - x²/at)
where E = energy
t = time
x = displacement.
so,
dimension of E = dimension of { b/at }
b/at = E
b/a = Et
dimension of {a/b} = 1/Et = 1/[ ML²T-²][ T]
= [ M-¹ L-²T]
Mark.as Brainlist ✔✔✔❤
★ Brainly Teacher ★
E = ( b -x²) /at
= ( b/at - x²/at)
where E = energy
t = time
x = displacement.
so,
dimension of E = dimension of { b/at }
b/at = E
b/a = Et
dimension of {a/b} = 1/Et = 1/[ ML²T-²][ T]
= [ M-¹ L-²T]
Mark.as Brainlist ✔✔✔❤
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