Write the dimension of (a/b) in the formula F=at+bx*2
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Force: M1 L1 T(-2)
so, dimensional formula of at and bt^2 is also M1 L1 T(-2)
Means, [aT] = M1L1T(-2)
SO, [a] = (M1 L1 T^-2)/T
so [a] = M1 L1 T -3
Same way for b,
bt^2= force
so b= force/t2 = m1 l1 t (-4)...
so, dimensional formula of at and bt^2 is also M1 L1 T(-2)
Means, [aT] = M1L1T(-2)
SO, [a] = (M1 L1 T^-2)/T
so [a] = M1 L1 T -3
Same way for b,
bt^2= force
so b= force/t2 = m1 l1 t (-4)...
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