Math, asked by yuvrajsingh8697, 10 months ago

write the disability rule of 2,6,5 with example​

Answers

Answered by Anonymous
1

Divisibility Test for 2: The last digit is 0, 2, 4, 6, or 8.

Divisibility Test for 3: The sum of the digits is divisible by 3.

Divisibility Test for 5: The last digit is 0 or 5.

Divisibility Test for 7: Cross off last digit, double it and subtract. Repeat if you want. If new number is divisible by 7, the original number is divisible by 7.

Answered by zoha25
3

hello dear mate

disability rule of 2 is that all the numbers should end with even numbers

like --352 is divided by 2 and we will get answers 176... hence we can divide 176 more by 2

disability rule of 6 is that if the number is divided by both 2 and 3 then it is also divided by 6

like number 324.. it is divisible by 2 and 3.. so it's also divisible by 6

disability rule of 5 is that the number should end with 5 or 0

Like numbers 125 or 130

so mate here is your answer. hope it helped u

if you don't mind can u please mark me as brainliest and also follow me

follow me

zoha25

Similar questions