Math, asked by akazel, 10 months ago

write the discriminant of 6x^+x-2=0​

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Answered by HimaniVarshney
4

a=6

b=1

c=-2

d =  \sqrt{b^{2}  - 4ac}  \\  \sqrt{1 ^{2}  - 4 \times 6 \times  - 2}  \\   \sqrt{1 + 48}  \\  \sqrt{49} \\ 7

thnxx

hope it helps you

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akazel: thank youmam
HimaniVarshney: My pleasure but I am not a teacher. I am also a student.
Answered by Anonymous
21
Answer:

Descriminant of the equation is 7.


Step-by-step explanation:


In a quadratic equation,

Descriminant (D) helps to know about the number of real solutions of that particular equation.

For example,

If D > O
then there will be 2 real and unequal solutions or roots of the eqn.

If D < 0
then there will be no real roots else imaginary roots.

If D = 0
then there will be two real and equal roots.

Now,

the given eqn. is

6x^2 + x -2

here

a = 6

b = 1

c= -2

as we know that

descriminant of a quadratic eqn is given by

D = √(b^2-4ac)

= √ [1^2 - 4×6×(-2)]

= ✓ (1+ 48)

= √ 49

= 7


sargamkashyap: haha..xD
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