Question

Write the discriminant of the give equationThis is maths previous year boards question. can any one solve​

Answer 1

since root is negative so no real exists.

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Answer 2

Answer

$\implies$ x = √31

$\huge\mathrm{Solution}$

(x + 5)² = 2(5x - 3)

$\implies$ x² + 25 + 10x = 10x - 6

$\implies$ x² = - 25 - 6

$\implies$ x² = - 31

$\implies$ x = √31

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