Question

Write the discriminant of the given quadratic equation x 2 + x - 12 = 0​

Answer 1

Answer:

Discriminant = 49

Step-by-step explanation:

d = b^2 - 4ac = (1)^2 - 4 * 1 * (-12) = 1 + 48 = 49

mark as brainliest!!

Answer 2

$\huge \: \green{ \boxed{ \red{ \purple{ \fbox{ \mathfrak{\bigstar{answer ♡}}}}}}}$

$\huge{ \red{ \ddot{ \smile}}}$

_______________________

${x}^{2} + x - 12 = 0 \\ \\ a = 1 \\ b = 1 \\ c = - 12 \\ \\ \boxed{ \fbox{ \green{ \mathfrak{discriminant = {b}^{2} - 4ac}}}}$

${1}^{2} - 4 \times 1 \times - 12 \\ = > 1 +48\\ = > 49 \\ 49 < 0$

which is smaller then 0,

so,this equation have 2 real roots.

____________________

hops this may help you

$\huge{ \red{ \ddot{ \smile}}}$

$\huge \blue{ \mathfrak{thanks♡</p><p>}}$