Question

Write the discriminant of the quadratic equation √2x2+7x+5√2=0​

Answer 1

Mark as Brainliest. Hope you understand, if any doubts, comment here, please. :D

Answer 2

In this question we are provided one quadratic equation and we need to find the discriminant of this quadratic equation. The quadratic equation is given below :

$\bullet\:\:\sf \sqrt{2}{x}^{2} + 7x + 5 \sqrt{2} = 0$

Now, compare the above quadratic equation with ax² + bx + c = 0 we get :

$\left[\begin{array}{c c c}\textsf{ \textbf{a}} &\textsf{ \textbf{b}}& \textsf{ \textbf{c}}\\\\ \sf \sqrt{2} & \sf 7 & \sf 5 \sqrt{2} \end{array}\right]$

$\dag \:\:\underline{\underline{\textsf{According to the Question Now :}}}$

$:\implies \sf Discriminant \: (D) = {b}^{2} - 4ac$

$:\implies \sf Discriminant \: (D) = {(7)}^{2} - 4 \times \sqrt{2} \times 5 \sqrt{2}$

$:\implies \sf Discriminant \: (D) = 49- 4 \times 5 \times 2$

$:\implies \sf Discriminant \: (D) = 49- 40$

$:\implies \underline{ \boxed{\sf Discriminant \: (D) = 9}}$

$\therefore\:\underline{\textsf{The discriminant of the given quadratic equation is \textbf{9}}}.$

Since,the Discriminant (D) > 0. Therefore the given quadratic equation has two distinct real roots.