Question

write the discriminant of the quadratic equation ax²+c=0​

Answer 1

Answer:

-4ac

Step-by-step explanation:

ax²+c=0

ax²+0x+ c=0

By comparing with standard equation i.e. ax²+bx+c = 0, we get

a= a , b = 0 , c= c

Thus, discriminant

= b²-4ac

= 0²-4(a)(c)

= -4ac

Answer 2

$\huge\underline\bold\red{Answer:-}$

Step by Step

ax² + c = 0

ax² + 0x + c = 0

By comparing with standard equation

We get,

a = a, b = 0, c = c

Thus

b² - 4ac

0² - 4 (a) (c)

- 4ac

Thanks!