Question

write the discriminant of the quadratic equation p
X square + q x minus R is equal to zero​

Answer 1

$px {}^{2} + qx - 6 = 0$

In the above equation,

a=p;b=q;c=-6

$b {}^{2} - 4ac$

$q {}^{2} \ - \: 4p \times ( - 6)$

$q {}^{2} - ( - 24p)$

$q {}^{2} + 24$

Is The Answer

Hope It Will Help You