Question

Write the discriminant of the quadratic equation (x + 5)^2 = 2 (5x - 3).​

Answer 1

${x }^{2} + 25 + 10x= 10x - 6 \\ {x}^{2} + 25 + 10x - 10x + 6 \\ {x}^{2} + 31 \\ d = {b}^{2} - 4ac \\ = {0}^{2} - 4(1)(31) \\ 0 - 124 \\ d \: = - 124$

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Answer 2

Answer:

Step-by-step explanation:

Given a quadratic equation :

x² + bx + c = 0

The discriminant is given by:

d = b² - 4ac

Where a , b and c are constants.

From the question we have :

(x + 5)² = 2(5x - 3)

x² + 10x + 25 = 10x - 6

Collecting the like terms together we have :

x² + 10x + 25 - 10x + 6 = 0

x² + 31 = 0

In our case :

b = o

c = 31

a = 1

Doing the substitution we have :

d = - 4 × 1 × 31 = -124

= -124