Question

write the discriminant of the quadratic equation X + 5 the whole square is equal to 2 bracket 5 x minus 3 close bracket​

Answer 1

$\huge\bf\pink{\mid{\overline{\underline{Your\: Answer}}}\mid}$

-124

step-by-step explanation:

Given,

${(x+5)}^{2}$=2(5x-3)

on expanding,

we get,

=> ${x}^{2}$+ 25 + 10x = 10x - 6

=> ${x}^{2}$ +25 + 6 = 0

=> ${x}^{2}$ + 31 = 0

=> ${x}^{2 }$ = -31

Here,

we see that,

the square of a number is equal to negative of a number.

But,

we know that square of any number cannot be negative,

So, the real value of roots of this equation is not possible.

It will be a complex number in terms of iota(í).


Now,

for descriminant,

${x}^{2}$ + 31 = 0

here,

a = 1

b = 0

c = 31

so,

descriminant (D) = ${b}^{2}$ - 4ac

=> D = 0 - 4×31×1

=> D = -124

Answer 2

Answer: The discriminant of the givenquadratic equation is -124.