Write the discriminant of the quafratic equation (x+5)^2=2(5x-3)
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X^2 +25+10x=10x-6
X^2+0x+31=0
a=1,b=0,c=31
Discriminant=b^2 - 4ac
=(0)^2 - 4(1)(31)=-124
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The penultimate statement is incorrect. Delta is -124, not greater than it.
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