Write the distance between the parallel planes 2x - y + 3z = 4 and 2x - y + 3z = 18.
Answers
Answered by
1
The distance between the two lines will be
= | c1-c2/√a^2+b^2+c^2 |
So,
Distance = | 18-4 / √(2^2 + 1^2 + 3^2) |
= 14/ √ 14 = √14 units
= | c1-c2/√a^2+b^2+c^2 |
So,
Distance = | 18-4 / √(2^2 + 1^2 + 3^2) |
= 14/ √ 14 = √14 units
Answered by
0
Step-by-step explanation:
Similar questions