Question

Write the distance of the point (3,-5, 12) form X-axis.​

Answer 1

The distance of the point (3,-5, 12) form X-axis.​ is 13 units.

Explanation:

Given : Point = (3,-5, 12)

Nearest point on x-axis = (3,0,0)   [∵x-coordinate remains same.]

Now , the distance between two points (a,b,c) and (d,e,f) is given by :

$\sqrt{(d-a)^2+(e-b)^2+(f-c)^2}$

Similarly , the distance between two points (3,-5, 12) and (3,0,0) will be :

$\sqrt{(3-3)^2+(0-(-5))^2+(0-12)^2}\\\\=\sqrt{0^2+(5)^2+(-12)^2}\\\\=\sqrt{25+144}\\\\=\sqrt{169}=13\text{ units}$

Hence, the distance of the point (3,-5, 12) form X-axis.​ is 13 units.

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