Write the distribution of electrons in carbon and sodium atoms
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Hence first shell (k -shell) have 2 electrons and 4 electrons will be present the second shell I. e. L - shell. Thus the distribution will be
K L
2 4
Atom no. I of sodium =11
hence, 1st shell and (k -shell) will have 2 electron and 2 shell (L-shell ) will have 8 electrons and 3 shell (M-shell) will have 1 electron. Thus the distribution will be
K L M
2 8 1
K L
2 4
Atom no. I of sodium =11
hence, 1st shell and (k -shell) will have 2 electron and 2 shell (L-shell ) will have 8 electrons and 3 shell (M-shell) will have 1 electron. Thus the distribution will be
K L M
2 8 1
Answered by
1
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❤The total number of electrons in a carbon atom is 6.❤
❤The distribution of electrons in carbon atom is given by:❤
❤First orbit or K-shell = 2 electrons❤
❤Second orbit or L-shell = 4 electrons❤
❤Or, we can write the distribution of electrons in a carbon atom as 2, 4.❤
❤The total number of electrons in a sodium atom is 11.❤
❤The distribution of electrons in sodium atom is given by:❤
❤First orbit or K-shell = 2 electrons❤
❤Second orbit or L-shell = 8 electrons❤
❤Third orbit or M-shell = 1 electron❤
❤Or, we can write distribution of electrons in a
sodium atom as 2, 8, 1.❤
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