write the divisibility rules for all composite numbers from 11 to 20
Answers
Answer:
Composite numbers between 1 to 10 4, 6, 8, 9, 10
Composite numbers between 11 to 20 12, 14, 15, 16, 18, 20
Hope it's will help you
Answer:
Divisibility by 11
A number is divisible by 11 if the difference of the sums of the alternate digits is 0 or a multiple of 11.
Divisibility by 12
If a number is divisible by both 3 and 4, then it is divisible by 12
Divisibility by 13
Subtract the last two digits from four times the rest. The result must be divisible by 13.
Divisibility by 14
The divisibility rule for 14 is that if the number is divisible by both 2 and 7 then the number is exactly divisible by 14.
Divisibility by 15
To be divisible by 15 a number has to be divisible by 3 and by 5. To be divisible by 5 the number must end in a 0 or a 5, easy enough.
Divisibility by 16
If the thousands digit is even, the number formed by the last three digits must be divisible by 16.
Divisibility by 17
Subtract five times the last digit from the remaining leading truncated number. If the result is divisible by 17, then so was the first number.
Divisibility by 18
A number that is divisible by 18 must be divisible by both 2 and 9. ... A number that is divisible by both 2 and 9 must be divisible by 18.
Divisibility by 19
Add two times the last digit to the remaining leading truncated number. If the result is divisible by 19, then so was the first number.
Divisibility by 20
Divisibility rule of 20 is that last two digits of the number are either 00 or divisible by 20 i.e. last two digits are either 00 , 20 , 40 , 60 or 80 .
pls mark me as a Brainliest