Math, asked by jiakher, 6 months ago

write the divisibility rules for all composite numbers from 11 to 20​

Answers

Answered by skkeshriecrpdayuh
1

Answer:

Composite numbers between 1 to 10 4, 6, 8, 9, 10

Composite numbers between 11 to 20 12, 14, 15, 16, 18, 20

Hope it's will help you

Answered by artigoyal123456789
1

Answer:

Divisibility by 11

A number is divisible by 11 if the difference of the sums of the alternate digits is 0 or a multiple of 11.

Divisibility by 12

If a number is divisible by both 3 and 4, then it is divisible by 12

Divisibility by 13

Subtract the last two digits from four times the rest. The result must be divisible by 13.

Divisibility by 14

The divisibility rule for 14 is that if the number is divisible by both 2 and 7 then the number is exactly divisible by 14.

Divisibility by 15

To be divisible by 15 a number has to be divisible by 3 and by 5. To be divisible by 5 the number must end in a 0 or a 5, easy enough.

Divisibility by 16

If the thousands digit is even, the number formed by the last three digits must be divisible by 16.

Divisibility by 17

Subtract five times the last digit from the remaining leading truncated number. If the result is divisible by 17, then so was the first number.

Divisibility by 18

A number that is divisible by 18 must be divisible by both 2 and 9. ... A number that is divisible by both 2 and 9 must be divisible by 18.

Divisibility by 19

Add two times the last digit to the remaining leading truncated number. If the result is divisible by 19, then so was the first number.

Divisibility by 20

Divisibility rule of 20 is that last two digits of the number are either 00 or divisible by 20 i.e. last two digits are either 00 , 20 , 40 , 60 or 80 .

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