write the divisibility rules of 2,4,3,5,6,8,9,10,11
Answers
Step-by-step explanation:
1
Any integer (not a fraction) is divisible by 1
2
The last digit is even (0,2,4,6,8)
128 Yes
129 No
3
The sum of the digits is divisible by 3
381 (3+8+1=12, and 12÷3 = 4) Yes
217 (2+1+7=10, and 10÷3 = 3 1/3) No
This rule can be repeated when needed:
99996 (9+9+9+9+6 = 42, then 4+2=6) Yes
4
The last 2 digits are divisible by 4
1312 is (12÷4=3) Yes
7019 is not (19÷4=4 3/4) No
A quick check (useful for small numbers) is to halve the number twice and the result is still a whole number.
12/2 = 6, 6/2 = 3, 3 is a whole number. Yes
30/2 = 15, 15/2 = 7.5 which is not a whole number. No
5
The last digit is 0 or 5
175 Yes
809 No
6
Is even and is divisible by 3 (it passes both the 2 rule and 3 rule above)
114 (it is even, and 1+1+4=6 and 6÷3 = 2) Yes
308 (it is even, but 3+0+8=11 and 11÷3 = 3 2/3) No8
The last three digits are divisible by 8
109816 (816÷8=102) Yes
216302 (302÷8=37 3/4) No
A quick check is to halve three times and the result is still a whole number:
816/2 = 408, 408/2 = 204, 204/2 = 102 Yes
302/2 = 151, 151/2 = 75.5 No
9
The sum of the digits is divisible by 9
(Note: This rule can be repeated when needed)
1629 (1+6+2+9=18, and again, 1+8=9) Yes
2013 (2+0+1+3=6) No
10
The number ends in 0
220 Yes
221 No
11If you sum every second digit and then subtract all other digits and the answer is: 0 or divisible by 11Example: 1364 ((3+4) - (1+6) =0) & 3729 ((7+9) - (3+2) = 11)
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