Question

write the division algorithm for 210 and 128​

Answer 1

Step-by-step explanation:

210>128 to get

210 = 128 × 1 +28,

128 = 82 × 1 + 46,

82 = 46 × 1 + 36,

46 = 36 × 1 + 10,

36 = 10 × 3 + 6

10 = 6 × 1 + 4

6 = 4 × 1 +2

4 = 2 × 2 + 0

So, the divisor at the stage is 2, the HCF of 210 And 128 is 2.

Answer 2

Step 1: Given Data

Given integers are $210$, $128$

HCF$=?$ using Division algorithm

Step 2: Calculating HCF using Euclid's division algorithm

Since, $210 > 128$,

$210=128\times 1+82\\128 = 82\times 1+ 46\\\\82 = 46\times 1+36\\46 = 36\times1+ 10\\36 = 10\times 3+6\\10 = 6\times 1+4\\6 = 4\times 1+2\\4 = 2\times 2 +0$

Here, remainder$=0$

Since, the divisor at this stage is $2$

Hence, the HCF of $210$ and $128$ is $2$.

#SPJ3