write the duals of x.(x+y)
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Answer:
(x.y)+(x.0)=x.(x+y).y
Explanation:
Given (x+y).(x+1)=x+x.y+y
to find dual of the given expression, we need to replace Ands i.e. '.' by
Or i.e. '+'
Or ('+') by Ands ('.'), 1 by 0 and we get
Dual of (x+y).(x+1)=x+x.y+y is
(x.y)+(x.0)=x.(x+y).y
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