Question

Write the electonic configuration for Fe3+,Cr3+,Pb2+,Pb4+,O2-

Answer 1

Fe3+   1s2 2s2 2p6 3s2 3p6 3d5
Cr3+   1s2 2s2 2p6 3s2 3p6 3d5 4s1
Pb2+  1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p6 6s2 4f14 5d10
Pb4+  1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p6 4f14 5d10
O2-     1s2 2s2 2p6

Answer 2

Electronic configuration for $Fe^{3+},Cr^{3+},Pb^{2+},Pb^{4+},O^{2-}.$

Explanation:

• To write electronic configuration of ions, first, the electronic configuration of the respective element must be written.
• To write it, the number of electrons present in an element must be known. We know that the atomic number represents the total number of electrons present in it.
• The superscript values given along with the elements indicates that gain or loss of electrons.
• If the value is in positive it means that the element has donated electrons and negative value indicates gain of the electrons.
• Accordingly electronic configuration of the given ions can be written as given in the attachment.

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