Question

Write the electronic configurarion of chromium. (z=24) and predict in it. a) number of subshell . b) number of elections in subshell having L=0. c) number of elections having n+L =3 . d) number of elections in hightest value of n. please any one?????​

Answer 1

Answer:

Cr-The electron configuration for chromium is 1s22s22p63s23p64s23d4.

However, in the case of chromium there is one empty d sub orbital, one of the electrons from the 4s orbital will move up to the 3d orbital and make the the actual electron configuration 1s22s22p63s23p64s13d5.

hope this helps you

Answer 2

Answer:

Cr = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹ 3d⁵

OR

[Ar] 4s¹ 3d⁵

Explanation:

Since n=3

No. of subshells are = 4

1. Number of electrons with L=0 are 12. Since there are 7 s electrons 4 $p_{z}$ electrons and 1 $d_{z^{2}}$ electrons.
2. N+L =3, are 8 since there are 6 and 2 electrons in $2p^{6}$ and $3s^{2}$ respectively
3. Highest value of n is 4, so 1 electron.