Write the electronic configuration iron ion in the following complex ion and predict its magnetic behavio
r :
[Fe(H2O)6]2+
Answers
Answer:
According to valence bond theory, there are two types of octahedral complexes are possible, namely, inner orbital complexes and outer orbital complexes.
When a transition or inner transition metals with a specific oxidation state forms octahedral complexes, then some of complexes are inner orbital and some of complexes are outer orbital.
Valence bond theory explained this matter on the basis of hybridization of metal ion.Now, in case of [Fe (H2O)6]2+ion, the oxidation state of Fe atom is 2+ and co-ordination number of central metal Fe(II)ion ionis 6.
The atomic number of Fe is 26 and that of ion (II) ion is 24. Hence, the valence shell electronic configuration of Fe (II) ion is [Ar] d6.
Now, according to valence bond theory, the electronic arrangement and hybridization of [Fe (H2O)6]2+ion is shown below.
Explanation:
Answer:
electronic configuration:-t2g⁴ eg²
magnetic behaviour:-paramagnetic