Question

Write the electronic configuration of a positively charged sodium ion (Na+ ). Atomic number of sodium is 11.​

Answer 1

Answer:

As we know that the atomic number of sodium is eleven. The number of electrons and protons of an atom is given by its atomic number. The electronic configuration of $Na$ is $(1{s^2},2{s^2},2{p^6},3{s^1})$.

Answer 2

Answer:

The systematic way to write the electronic configuration of $Na^{+}$ is $1s^{2} 2s^{2} 2p^{6}$.

Explanation:

• Sodium lies in the first group of the s- block.
• The atomic number of sodium is 11.
• When it loses one electron, it gains a positive charge.

Before the loss of an electron-

→ Electronic configuration of $Na$: 2, 8, 1

→ Systematic electronic configuration of $Na$: $1s^{2} 2s^{2} 2^{6} 3s^{1}$

After the loss of an electron-

→  Electronic configuration of $Na^{+}$: 2, 8

→ Systematic electronic configuration of $Na^{+}$: $1s^{2} 2s^{2} 2^{6}$

Conclusion:

The electronic configuration of $Na^{+}$ (sodium ion) $1s^{2} 2s^{2} 2p^{6}$.