write the electronic configuration of a positively charged sodium ion (Na`)
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na ion mean that na has donated electron therefore electronic configuration is 2,8
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The normal sodium ion
This has 11 protons
Hence there are 11 electrons .
Configuration = 2 , 8 , 1
Positively charged ion
Now when there is a loss of electron , the sodium becomes positively charged
The valence electron is lost from sodium .
The configuration becomes 2 , 8 after losing one electron
Answer
The configuration is 2 , 8
Hope it helps :-)
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