Chemistry, asked by raja8337, 5 months ago

write the electronic configuration of an element just below that of 1s2 2s2 2p3 in the periodic table

Answers

Answered by snehaprajnaindia204

1

Answer:

1s² 2s² 2p³ = 2, 5

.

$N_{7} =$ 1s² 2s² 2p³

Explanation:

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