write the electronic configuration of chromium.write the value of n and l for its electron in the valence shell how many unpaired electrons are present in it
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electronic configuration of chromium is [Ar] 4s1 3d9 it is an exception case so you have to remember it
n= 4 and 3 and l= 0 and 2
unpaired electrons is 1
n= 4 and 3 and l= 0 and 2
unpaired electrons is 1
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