Question

Write the electronic configuration of cr3+(z = 24).

Answer 1

The electronic configuration will be -
(2,8,11). (1s²,2s²,2p6, 3s², 3p6,4s^0, 3d³)

As it is given that chromium has 3+ valency, so it will loose 3 electrons.

Thus 24-3= 21

Answer 2

Answer:

The electronic configuration in the ground state is

Cr (Z = 24) = $1s^2, 2s^2 2p^6 3s^2 3p^6 4s^1 3d^5.$

Explanation:

The atomic number of chromium = 24.

The electronic configuration in the ground state is

Cr (Z = 24) = $1s^2, 2s^2 2p^6 3s^2 3p^6 4s^1 3d^5.$

The electronic configuration of cr3+ is

$cr3+ = 1s^2, 2s^2 2p^6 3s^2 3p^6 4s^0 3d^3.$

There are three unpaired electrons present in the 3d subshell.

The number of unpaired electrons in Cr3+ ions is = 3.