Question

write the Electronic configuration of elements upto 1 to 30 ​

Answer 1

EXPLANATION:

1. Hydrogen (H) -------->1s¹
2. Helium (He) ----------->1s²
3. Lithium (Li) ------------->[He] 2s¹
4. Beryllium (Be)--------->[He] 2s²
5. Boron (B)--------------->[He]2s² 2p¹
6. Carbon (C)------------->[He] 2s² 2p²
7. Nitrogen (N)----------->[He] 2s² 2p³
8. Oxygen (O)------------>[He] 2s² 2p⁴
9. Fluorine (F)------------>[He] 2s² 2p⁵
10. Neon (Ne) ------—----->[He] 2s² 2p⁶
11. Sodium (Na)----------->[Ne] 3s¹
12. Magnesium (Mg)---->[Ne] 3s²
13. Aluminium (Al)------->[Ne] 3s² 3p¹
14. Silicon (Si)------------->[Ne] 3s² 3p²
15. Phosphorus (P)------>[Ne] 3s² 3p³
16. Sulphur (S)------------>[Ne] 3s² 3p⁴
17. Chlorine (Cl)---------->[Ne] 3s² 3p⁵
18. Argon (Ar)-------------->[Ne] 3s² 3p⁶
19. Potassium (K)--------->[Ar] 4s¹
20. Calcium (Ca)---------->[Ar] 4s²
21. Scandium (Sc)-------->[Ar] 3d¹ 4s²
22. Titanium (Ti)----------->[Ar] 3d² 4s²
23. Vanadium (V)---------->[Ar] 3d³ 4s²
24. Chromium (Cr) ------->[Ar] 3d⁵ 4s¹
25. Manganese (Mn) ----->[Ar] 3d⁵ 4s²
26. Iron (Fe)------------------>[Ar] 3d⁶ 4s²
27. Cobalt (Co)-------------->[Ar] 3d⁷ 4s²
28. Nickel (Ni)---------------->[Ar] 3d⁸ 4s²
29. Copper (Cu) ------------>[Ar] 3d¹⁰ 4s¹
30. Zinc (Zn)------------------->[Ar] 3d¹⁰ 4s²

Here Cr [Ar] 3d⁵ 4s¹ and Cu [Ar] 3d¹⁰ 4s² possess exceptional electronic configuration. So they can attain the stable 3d⁵ and 3d¹⁰ electronic configuration respectively.

Note: Alphabets inside the brackets ( ) indicate the symbols and alphabets inside the square bracket [ ] indicates the symbol of inert gas present before the particular element.