Question

Write the electronic configuration of fe^+2and Cr​

Answer 1

Answer:

The electronic configuration of Fe2+ is

1s2 2s2 2p6 3s2 3p6 3d6

Answer 2

Solution :

(1)$\sf{}Fe ^{2+}$

Here, atomic number of Fe is 9 and it is loosing two electrons therefore, atomic number becomes (9-2) = 7.

Electronic configuration: 1s² 2s² 2p³

(2)$\sf{Cr}$

Here, atomic number of Cr is 24.

Electronic configuration: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹ 3d⁵

More to know:

Rules :-

• Paule's Exclusion Principle

It states that no two electrons could have same set of Quantum numbers.

It also states that only two electrons can accommodate in same orbital.

• Aufbau's Principle

It states that in ground state of atom the filling of an electron in the orbital takes place in increasing order of their energy.

• Bohr Bury rule

The orbitals with the lesser value for (n+l) is filled before with greater value of (n+l ).