Question

write the electronic configuration of H2 molecule what is its bond order

Answer 1

Electronic configuration: σ1s²

Bond order=1/2[number of bonding electrons -number of antibonding electrons]

=1/2[2]

=1.

Answer 2

The electronic configuration of the hydrogen molecule is $\sigma^2_{1s} \sigma^2_{1s}*$.

• Hydrogen molecule consists of two electrons in its sigma bonding molecular orbital and zero electrons in its sigma antibonding molecular orbital.
• Hence the electronic configuration of the hydrogen molecule is as follows-
• $\sigma^2_{1s} \sigma^2_{1s}*$.
• Now bond order is given as-
• The number of bonding electrons-number of antibonding electrons/2
• (2-0)/2=1.
• Thus, the bond order of hydrogen molecules is 1.